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Message: <blockquote data-quote="Justinh722" data-source="post: 5146373" data-attributes="member: 545828">So I have 2 4" ports that are 7.75 inches long. My surface area for the ports is 25.1 sq in of port. Then I would take 25.1 x 15.5 =  389 then I divide that by 1728 which gives me .225 cu ft of port displacement. Does that sound right?I have a 4 cu ft box after sub displacement for my 12" solo x. So technically it's only a 3.8 cu ft box with the port displacement? It seems like I should have more than 25 sq inches of port for my sub.Would I need a Lot of port area if my box for my 10" stroker is only 1.5 cu ft or less? How do people design boxes and factor in the port area before their intended volume?</blockquote>

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