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<blockquote data-quote="fatryan" data-source="post: 3479868" data-attributes="member: 550026">no offense but i dont really see how those lessons even explained anything about the issue this forum has with caps.but let me put it this way:&nbsp; caps charge and discharge with the same time constant (tou=RC).&nbsp; that said, they charge and discharge at the same rate.&nbsp; take a look at graphs of a cap charging and discharging, they are exact inverses of eachother with the time constant at the same point in both graphs.&nbsp; my point behind this is that its untrue to claim that a cap &quot;steals&quot; the current from the amp to recharge itself because at the same time it takes an equal time to discharge.&nbsp; as claimed about everything in a circuit (bat, cap, amp) all have an internal resistance therefore the cap wont &quot;instantly&quot; discharge when the amp needs current.&nbsp; if it did instantly discharge it would HAVE TO instantly charge then too.&nbsp; and on top of that when the cap starts feeding the amp that doesnt mean that the electrical system stops feeding the amp too.&nbsp; you could also simply measure the voltage changes during a time of heavy current draw in your system when a cap is installed and not installed.&nbsp; youll find that the voltage difference between the 2 would be very minimal if even measurable.&nbsp; and since resistance is constant (internal resistance is essentially 0 when compared to other resistors in the circuit), ohm&#039;s law then tells us that current is directly proportional to voltage...current in = current out.im not saying a cap HELPS anything.&nbsp; it doesnt, it just protects your electrical system givin specific circumstances.&nbsp; its use in a car audio DC circuit is very limited, but i still believe it has its place.</blockquote>

[QUOTE="fatryan, post: 3479868, member: 550026"] no offense but i dont really see how those lessons even explained anything about the issue this forum has with caps. but let me put it this way: caps charge and discharge with the same time constant (tou=RC). that said, they charge and discharge at the same rate. take a look at graphs of a cap charging and discharging, they are exact inverses of eachother with the time constant at the same point in both graphs. my point behind this is that its untrue to claim that a cap "steals" the current from the amp to recharge itself because at the same time it takes an equal time to discharge. as claimed about everything in a circuit (bat, cap, amp) all have an internal resistance therefore the cap wont "instantly" discharge when the amp needs current. if it did instantly discharge it would HAVE TO instantly charge then too. and on top of that when the cap starts feeding the amp that doesnt mean that the electrical system stops feeding the amp too. you could also simply measure the voltage changes during a time of heavy current draw in your system when a cap is installed and not installed. youll find that the voltage difference between the 2 would be very minimal if even measurable. and since resistance is constant (internal resistance is essentially 0 when compared to other resistors in the circuit), ohm's law then tells us that current is directly proportional to voltage...current in = current out. im not saying a cap HELPS anything. it doesnt, it just protects your electrical system givin specific circumstances. its use in a car audio DC circuit is very limited, but i still believe it has its place. [/QUOTE]

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