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wiring 4 component sets
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<blockquote data-quote="fwb_1234" data-source="post: 3961989" data-attributes="member: 573700"><p>OK</p><p></p><p>4 sets means: 8 midbass, 8 passive crossovers, and 8 tweets.</p><p></p><p>Each of the four sets has a 4 ohm impedance, measured at the crossover. That means that you have eight 4 ohm loads.</p><p></p><p>Most amps can do a two ohm load, look into it. I would match up pairs of components in parallel, so that you get four 2 ohm loads, which you could then hook up to the four channels of your amp.</p><p></p><p>-or-</p><p></p><p>You could, as above match up pairs of components in parallel into four 2ohm loads. Then put two of the 2ohm loads in series to leave you with two four ohm loads. You could then bridge your amp to run two channels at 4 ohms.</p></blockquote><p></p>
[QUOTE="fwb_1234, post: 3961989, member: 573700"] OK 4 sets means: 8 midbass, 8 passive crossovers, and 8 tweets. Each of the four sets has a 4 ohm impedance, measured at the crossover. That means that you have eight 4 ohm loads. Most amps can do a two ohm load, look into it. I would match up pairs of components in parallel, so that you get four 2 ohm loads, which you could then hook up to the four channels of your amp. -or- You could, as above match up pairs of components in parallel into four 2ohm loads. Then put two of the 2ohm loads in series to leave you with two four ohm loads. You could then bridge your amp to run two channels at 4 ohms. [/QUOTE]
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