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<blockquote data-quote="IgnoreMe" data-source="post: 3510363" data-attributes="member: 551352">i know that ng, im just wondering why the resistance of the physical coil actually changes.i mean if i hook my dmm up to a 2 ohm resistor, i can move it, kick it, piss on it (well maybe not that), and it will always read 2 ohms.so why, when i hooked up to the coil ( something that has a given resistance), does the resistance change, when you would expect it to stay the same. i mean, when the cone moves, the coil doesnt change its properties, yet the resistance still changes. if i were to take the coil out, set it down, and measure it, it would always give me 1 reading, but when its in the motor its resistance properties change.helotaxi explained it to me, but he mentioned actual current running through the coil a couple times in the post. i forgot to mention i was talking about no power in the circuit (as i explained earlier, so that there is no variables). so im just trying to basically understand if his explanation is also accurate for when there is no power in the circuit.</blockquote>

[QUOTE="IgnoreMe, post: 3510363, member: 551352"] i know that ng, im just wondering why the resistance of the physical coil actually changes. i mean if i hook my dmm up to a 2 ohm resistor, i can move it, kick it, piss on it (well maybe not that), and it will always read 2 ohms. so why, when i hooked up to the coil ( something that has a given resistance), does the resistance change, when you would expect it to stay the same. i mean, when the cone moves, the coil doesnt change its properties, yet the resistance still changes. if i were to take the coil out, set it down, and measure it, it would always give me 1 reading, but when its in the motor its resistance properties change. helotaxi explained it to me, but he mentioned actual current running through the coil a couple times in the post. i forgot to mention i was talking about no power in the circuit (as i explained earlier, so that there is no variables). so im just trying to basically understand if his explanation is also accurate for when there is no power in the circuit. [/QUOTE]

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