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<blockquote data-quote="squeak9798" data-source="post: 1999535" data-attributes="member: 555320">It does, if you understand how the amplifier operates........though it&#039;s not really more than 100% efficient, it doesn&#039;t create it&#039;s own power.....it simply draws and dispenses the current at different than &quot;typical&quot; times, so there are points in it&#039;s operation that it&#039;s outputting more power than it&#039;s drawing from the electrical system (this is where they, IMO mistakenly, label it as &quot;more than&quot; 100% efficient).&nbsp; But it must replenish this power, hence you aren&#039;t really gaining any power in the long run...you&#039;re just redistributing it&#039;s consumption.Basically, the amplifier has a huge, huge internal capacitance bank.&nbsp; This bank is used to store large amounts of current so that at times of high output, instead of drawing high peak current from the electrical system it draws the excess required current from it&#039;s own internal capacitor bank.&nbsp; However, after the large output subsides, the amplifier is still drawing high amounts of current due the fact that it must now replenish the current it used from the capacitor bank.&nbsp; Essentially all the amplifier is doing is trading off less peak current consumption for higher average current consumption, and due to the high amount of capacitance it severely limits how long it can actually output it&#039;s &quot;rated continuous&quot; power for to ~16 seconds (under favorable assumptions...basically best case scenario).Good read, pay special attention to the posts by werewolf as he does a very good job of explaining and mathmatically proving the physics by which this amplifier operates:<a href="http://www.audiogroupforum.com/csforum/showthread.php?t=41104&amp;amp;page=5" target="_blank">http://www.audiogroupforum.com/csforum/showthread.php?t=41104&amp;amp;page=5</a> (starting you out on page 5, you can read from the beginning of the thread but it doesn&#039;t really become educational until werewolf starts posting in it)</blockquote>

[QUOTE="squeak9798, post: 1999535, member: 555320"] It does, if you understand how the amplifier operates........though it's not really [I]more than[/I] 100% efficient, it doesn't [I]create[/I] it's own power.....it simply draws and dispenses the current at different than "typical" times, so there are points in it's operation that it's outputting more power than it's drawing from the electrical system (this is where they, IMO mistakenly, label it as "more than" 100% efficient). But it must replenish this power, hence you aren't really [I]gaining[/I] any power in the long run...you're just redistributing it's consumption. Basically, the amplifier has a huge, huge internal capacitance bank. This bank is used to store large amounts of current so that at times of high output, instead of drawing high peak current from the electrical system it draws the excess required current from it's own internal capacitor bank. However, after the large output subsides, the amplifier is still drawing high amounts of current due the fact that it must now replenish the current it used from the capacitor bank. Essentially all the amplifier is doing is trading off less peak current consumption for higher average current consumption, and due to the high amount of capacitance it severely limits how long it can actually output it's "rated continuous" power for to ~16 seconds (under [I]favorable[/I] assumptions...basically best case scenario). Good read, pay special attention to the posts by werewolf as he does a very good job of explaining and mathmatically proving the physics by which this amplifier operates: [URL="http://www.audiogroupforum.com/csforum/showthread.php?t=41104&page=5"]http://www.audiogroupforum.com/csforum/showthread.php?t=41104&page=5[/URL] (starting you out on page 5, you can read from the beginning of the thread but it doesn't really become educational until werewolf starts posting in it) [/QUOTE]

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