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Car Audio Discussion
General Car Audio
What is louder? More cone area, more power, or more drivers?
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<blockquote data-quote="SounDrive" data-source="post: 8552483" data-attributes="member: 653833"><p>A good quick way to estimate is as follows, higher is better. This is not 100% accurate, but is a better method than any other I've seen to date. This doesn't take into consideration anything but raw efficiency. You also have to consider power compression, linear excursion, etc.</p><p></p><p>[(BL^2/RE)/MMS]*SD*Number of Subs</p><p></p><p>To break it down:</p><p></p><p>(BL^2/RE) = motor force "factor". Motor force without resistance factored in. You can grab these specs from the TS of the sub.</p><p></p><p>MMS = moving mass. Less moving mass, given the same motor force, means a more efficient sub</p><p></p><p>SD = piston area of a sub, this is a tad more accurate than just using cone area. Multiply this by number of subs to get total piston area</p></blockquote><p></p>
[QUOTE="SounDrive, post: 8552483, member: 653833"] A good quick way to estimate is as follows, higher is better. This is not 100% accurate, but is a better method than any other I've seen to date. This doesn't take into consideration anything but raw efficiency. You also have to consider power compression, linear excursion, etc. [(BL^2/RE)/MMS]*SD*Number of Subs To break it down: (BL^2/RE) = motor force "factor". Motor force without resistance factored in. You can grab these specs from the TS of the sub. MMS = moving mass. Less moving mass, given the same motor force, means a more efficient sub SD = piston area of a sub, this is a tad more accurate than just using cone area. Multiply this by number of subs to get total piston area [/QUOTE]
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What is louder? More cone area, more power, or more drivers?
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