Reply to thread

Message

<blockquote data-quote="Synastr" data-source="post: 8202524" data-attributes="member: 657828"><p>No no, I tried each sub separately. One sub wired up to the amp. Then unhooked and the other wired. Never had both wired at the same time otherwise I&#039;d have to rewire to get 2ohm load. So I took the better sounding box today and turned all things to zero. Zero bass boost on radio. All gain knobs down. Set the subsonic at 25hz. Set the bass boost to about 1/4 up. Set crossover to about 60hz. Turned the radio up to a good level and went to adjusting to gain, right as it started to be loud but not distort or be up to far. (Which didn&#039;t get far) I unhooked the sub and read my DMM at 40hz and ended up reading almost 15volts which equates to a little over 200 watts roughly. I believe all is lead to the box, because if you play a punchy song, you can increase the gain and it doesn&#039;t distort. I read the voltage then and it&#039;s about 20, which means roughly 380-400 watts according to a 1ohm formula.&nbsp; Which is voltage = the square root of watts x ohms.</p></blockquote><p></p>

[QUOTE="Synastr, post: 8202524, member: 657828"] No no, I tried each sub separately. One sub wired up to the amp. Then unhooked and the other wired. Never had both wired at the same time otherwise I'd have to rewire to get 2ohm load. So I took the better sounding box today and turned all things to zero. Zero bass boost on radio. All gain knobs down. Set the subsonic at 25hz. Set the bass boost to about 1/4 up. Set crossover to about 60hz. Turned the radio up to a good level and went to adjusting to gain, right as it started to be loud but not distort or be up to far. (Which didn't get far) I unhooked the sub and read my DMM at 40hz and ended up reading almost 15volts which equates to a little over 200 watts roughly. I believe all is lead to the box, because if you play a punchy song, you can increase the gain and it doesn't distort. I read the voltage then and it's about 20, which means roughly 380-400 watts according to a 1ohm formula. Which is voltage = the square root of watts x ohms. [/QUOTE]

Verification