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<blockquote data-quote="sumone" data-source="post: 1232422" data-attributes="member: 551481"><p>Are you looking for variance or standard deviation?</p><p></p><p>if variance, take the mean of all trials; call it M.</p><p></p><p>add the total of (M-nT)^2 where M is the mean you just found &amp; nT is the value for trial "n"</p><p></p><p>divide this total by number of trials minus 1 (n-1, since I'm guessing this is an unbiased calculation)</p><p></p><p>that gives you the mean(average) variance</p><p></p><p>take the square root if you want standard deviation.</p><p></p><p>ex:</p><p></p><p>n1 = 1, n2=2, n2=3</p><p></p><p>M = (1+2+3)/3 = 6/3 = 2</p><p></p><p>(M-n1)^2 + (M-n2)^2 + (M-n3)^2 = (2-1)^2 + (2-2)^2 + (2-3)^2 = 1 + 0 + 1 = 2</p><p></p><p>divided by n-1 = 2 / (3 - 1) = 2/2 = 1</p></blockquote><p></p>
[QUOTE="sumone, post: 1232422, member: 551481"] Are you looking for variance or standard deviation? if variance, take the mean of all trials; call it M. add the total of (M-nT)^2 where M is the mean you just found & nT is the value for trial "n" divide this total by number of trials minus 1 (n-1, since I'm guessing this is an unbiased calculation) that gives you the mean(average) variance take the square root if you want standard deviation. ex: n1 = 1, n2=2, n2=3 M = (1+2+3)/3 = 6/3 = 2 (M-n1)^2 + (M-n2)^2 + (M-n3)^2 = (2-1)^2 + (2-2)^2 + (2-3)^2 = 1 + 0 + 1 = 2 divided by n-1 = 2 / (3 - 1) = 2/2 = 1 [/QUOTE]
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