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<blockquote data-quote="RAM_Designs" data-source="post: 7732133" data-attributes="member: 566575">32&quot; wide x 16&quot; tall x 18&quot; deep = 4.22ft^3 before sub and port displacements.Two ports, each with 14.5&quot; tall x 3.75&quot; wide x 12&quot;(rounding) worth of displacements = ~.75ft^3So now we&#039;re at 3.47ft^3 without sub displacement.&nbsp; After sub displacement we&#039;re at 3.28ft^3.Now, a 3.28ft^3 box with a pair of 14.5&quot;x3&quot; ports that have a total effective length of ~13&quot; each gives you a tuning in the low 60&#039;s. ---------- Post added at 09:51 PM ---------- Previous post was at 09:51 PM ---------- With dual ports you DO NOT split the port length in half.&nbsp; Each port has to be the calculated length.</blockquote>

[QUOTE="RAM_Designs, post: 7732133, member: 566575"] 32" wide x 16" tall x 18" deep = 4.22ft^3 before sub and port displacements. Two ports, each with 14.5" tall x 3.75" wide x 12"(rounding) worth of displacements = ~.75ft^3 So now we're at 3.47ft^3 without sub displacement. After sub displacement we're at 3.28ft^3. Now, a 3.28ft^3 box with a pair of 14.5"x3" ports that have a total effective length of ~13" each gives you a tuning in the low 60's. [COLOR=Silver] [/COLOR] [COLOR=Silver][SIZE=8px]---------- Post added at 09:51 PM ---------- Previous post was at 09:51 PM ----------[/SIZE][/COLOR][SIZE=8px][/SIZE] [COLOR=Silver] [/COLOR] With dual ports you DO NOT split the port length in half. Each port has to be the calculated length. [/QUOTE]

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