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Setting Gain Perfectly
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<blockquote data-quote="PV Audio" data-source="post: 5961442" data-attributes="member: 554493"><p>Just in case anyone didn't know (it sounds like pretty random math), all this is is ohm's law using the power equivalency P=IV with a substitution. V=IR is ohm's law which means that I=V/R. Plug that into P=IV and you have V^2/R. You're just solving for the output voltage that can make the power you need RMS (maximum output power divided by the square root of two) with the impedance of the sub. Make note to do this impedance calculation with the sub NOT connected to anything or playing as the impedance will be all over the place due to inductive effects.</p><p></p><p>Just in case anyone was wondering. //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif</p></blockquote><p></p>
[QUOTE="PV Audio, post: 5961442, member: 554493"] Just in case anyone didn't know (it sounds like pretty random math), all this is is ohm's law using the power equivalency P=IV with a substitution. V=IR is ohm's law which means that I=V/R. Plug that into P=IV and you have V^2/R. You're just solving for the output voltage that can make the power you need RMS (maximum output power divided by the square root of two) with the impedance of the sub. Make note to do this impedance calculation with the sub NOT connected to anything or playing as the impedance will be all over the place due to inductive effects. Just in case anyone was wondering. [IMG]//content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif[/IMG] [/QUOTE]
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