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Series/Parallel Ohm, Watts Problem
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<blockquote data-quote="maylar" data-source="post: 999129" data-attributes="member: 541144"><p>Actually... in your case it might be the correct solution, if you really want to run 3 speakers. A 4 ohm resistor in series with speaker 3 would make two 8-ohm pairs in parallel, giving 4 ohms total. The 65 watts would be divided 4 ways equally (including the resistor). 16 watts to 3.5's is just about right, and all 3 would be at the same volume.</p><p></p><p>Normally I recommend against resistors for impedance matching but in your case it kinda makes sense. So you waste 16 watts in heat. Oh well.</p><p></p><p>Make sure you get at least a 50 watt 4 ohm resistor and heatsink it to some metal.</p></blockquote><p></p>
[QUOTE="maylar, post: 999129, member: 541144"] Actually... in your case it might be the correct solution, if you really want to run 3 speakers. A 4 ohm resistor in series with speaker 3 would make two 8-ohm pairs in parallel, giving 4 ohms total. The 65 watts would be divided 4 ways equally (including the resistor). 16 watts to 3.5's is just about right, and all 3 would be at the same volume. Normally I recommend against resistors for impedance matching but in your case it kinda makes sense. So you waste 16 watts in heat. Oh well. Make sure you get at least a 50 watt 4 ohm resistor and heatsink it to some metal. [/QUOTE]
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