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Series/Parallel Ohm, Watts Problem
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<blockquote data-quote="maylar" data-source="post: 996936" data-attributes="member: 541144"><p>Impedance calculation is correct.</p><p></p><p>The amp will do somewhere between 65 and 100 watts with 2.66 ohms.</p><p></p><p>P = (E^2)/R</p><p></p><p>therefore E = sq rt of (P*R)</p><p></p><p>For 100 watts @ 2 ohms E = 14.14 volts</p><p></p><p>For 65 watts @ 4 ohms, E = 16.12 volts</p><p></p><p>Therefore assuming the amp would output 15 volts at 2.66 ohms:</p><p></p><p>P = (15^2)/4 = 56 watts for speaker #3</p><p></p><p>P = (15^2)/8 = 28 watts for the 8 ohm combo of speakers 1 &amp; 2. Each would get half.</p></blockquote><p></p>
[QUOTE="maylar, post: 996936, member: 541144"] Impedance calculation is correct. The amp will do somewhere between 65 and 100 watts with 2.66 ohms. P = (E^2)/R therefore E = sq rt of (P*R) For 100 watts @ 2 ohms E = 14.14 volts For 65 watts @ 4 ohms, E = 16.12 volts Therefore assuming the amp would output 15 volts at 2.66 ohms: P = (15^2)/4 = 56 watts for speaker #3 P = (15^2)/8 = 28 watts for the 8 ohm combo of speakers 1 & 2. Each would get half. [/QUOTE]
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