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Running woofers at different independences
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<blockquote data-quote="mikey7182" data-source="post: 4023988" data-attributes="member: 580809"><p>Well if you run something in series parallel, you are essentially doing the same thing as far as I know. And you wouldn't end up at .8 ohms, you'd end up back at 2. When you wire in series parallel, normally you make each DVC 2 ohm sub a 4 ohm sub by wiring the VCs in series, then wire in parallel to get back to 2 ohms, or down to 1 ohm by wiring the VCs in parallel, then back up to 2 by wiring the subs in series... Now if you are using 2 subs that have different impedances, say a Single 4 ohm sub and a single 2 ohm sub, that may be different. I don't know enough about it, but I would think that the subs would see different power, but if they are in the same circuit (all run off 1 channel) maybe they will see the same amount of power. I don't know if the individual impedance of each speaker determines its draw, or if both speakers' impedances determine the final draw on the amp, then have the power dispersed evenly... Hopefully that answers your question.</p></blockquote><p></p>
[QUOTE="mikey7182, post: 4023988, member: 580809"] Well if you run something in series parallel, you are essentially doing the same thing as far as I know. And you wouldn't end up at .8 ohms, you'd end up back at 2. When you wire in series parallel, normally you make each DVC 2 ohm sub a 4 ohm sub by wiring the VCs in series, then wire in parallel to get back to 2 ohms, or down to 1 ohm by wiring the VCs in parallel, then back up to 2 by wiring the subs in series... Now if you are using 2 subs that have different impedances, say a Single 4 ohm sub and a single 2 ohm sub, that may be different. I don't know enough about it, but I would think that the subs would see different power, but if they are in the same circuit (all run off 1 channel) maybe they will see the same amount of power. I don't know if the individual impedance of each speaker determines its draw, or if both speakers' impedances determine the final draw on the amp, then have the power dispersed evenly... Hopefully that answers your question. [/QUOTE]
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