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<blockquote data-quote="helotaxi" data-source="post: 3640550" data-attributes="member: 550915"><p>If you go to the trouble of learning how loads are summed in different wiring configurations, all wiring problems become really simple.&nbsp; You don&#039;t have to &quot;think of it as...&quot; you just treat each individual coil as its own load every time and do the math.&nbsp; Even the math is simple, the calculator on the computer is all you need.&nbsp; Doesn&#039;t even have to be in scientific mode.&nbsp; You only need the + key the 1/x key and the = key to do any resistive circuit math.&nbsp; For series wiring you add the values of the loads wired in series.&nbsp; Simple math.&nbsp; For parallel wiring you do the same thing except press the 1/x key after the value of each load.&nbsp; You want to add the inverse (1/x) value of each load.&nbsp; Once you have them all added hit = and then hit the 1/x key again.&nbsp; The way of stating the resultant load of resistive loads wired in parallel is the inverse of the sum of the inverses.</p></blockquote><p></p>

[QUOTE="helotaxi, post: 3640550, member: 550915"] If you go to the trouble of learning how loads are summed in different wiring configurations, all wiring problems become really simple. You don't have to "think of it as..." you just treat each individual coil as its own load every time and do the math. Even the math is simple, the calculator on the computer is all you need. Doesn't even have to be in scientific mode. You only need the + key the 1/x key and the = key to do any resistive circuit math. For series wiring you add the values of the loads wired in series. Simple math. For parallel wiring you do the same thing except press the 1/x key after the value of each load. You want to add the inverse (1/x) value of each load. Once you have them all added hit = and then hit the 1/x key again. The way of stating the resultant load of resistive loads wired in parallel is the inverse of the sum of the inverses. [/QUOTE]

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