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Question on How to Measure Port length-2 diff. designs
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<blockquote data-quote="Texas Tech" data-source="post: 2730359" data-attributes="member: 574603"><p>physical length+length to center point from end of physical port and rear wall of enclosure+length of center point to one side of the port (including the woods thickness)</p><p></p><p>i got it now but i still have one question that i have to ask....</p><p></p><p>The measuring to the middle point makes sense for end correction and all,</p><p></p><p>but the measuring to one side is my question...why do you only measure to one side, why would you not measure to both sides, so instead of it being 2.25 it would be 4.5. But this will answer my question. You said accounted for port area, So that is only calculated in with port area?</p><p></p><p>So is 18.75 the effective length. That is the length i would put into my equation to find out what a port is tuned to.</p><p></p><p>And the Port Area would be 15(3)+1.5(2.25)</p><p></p><p>So it equals 48.375 square inches.</p></blockquote><p></p>
[QUOTE="Texas Tech, post: 2730359, member: 574603"] physical length+length to center point from end of physical port and rear wall of enclosure+length of center point to one side of the port (including the woods thickness) i got it now but i still have one question that i have to ask.... The measuring to the middle point makes sense for end correction and all, but the measuring to one side is my question...why do you only measure to one side, why would you not measure to both sides, so instead of it being 2.25 it would be 4.5. But this will answer my question. You said accounted for port area, So that is only calculated in with port area? So is 18.75 the effective length. That is the length i would put into my equation to find out what a port is tuned to. And the Port Area would be 15(3)+1.5(2.25) So it equals 48.375 square inches. [/QUOTE]
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