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Q's about a 13W7...
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<blockquote data-quote="d audio 450" data-source="post: 278887" data-attributes="member: 545894"><p>actually no....its only 12v......so take 12, divide it by the impedence of your sub, and thats your current (in amps). take the current value and multiply it by 12v...thats how much power your sub would be using while hooked up to a 12v...</p><p></p><p>-pat</p><p></p><p>edit: but keep in mind...with that 12v....in free air, its quite possible to throw the sub to full excursion immediatley...wouldnt consider it good for the sub...</p></blockquote><p></p>
[QUOTE="d audio 450, post: 278887, member: 545894"] actually no....its only 12v......so take 12, divide it by the impedence of your sub, and thats your current (in amps). take the current value and multiply it by 12v...thats how much power your sub would be using while hooked up to a 12v... -pat edit: but keep in mind...with that 12v....in free air, its quite possible to throw the sub to full excursion immediatley...wouldnt consider it good for the sub... [/QUOTE]
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