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<blockquote data-quote="thch" data-source="post: 1483995" data-attributes="member: 562032">common misconception.&nbsp; the input siganl from the RCA&#039;s is a control signal -- it provides insignifigant energy for the amp to actually do anything.&nbsp; with transistors it is easy to get a voltage gain of over 10,000.&nbsp; in fact that&#039;s how amps end up working.&nbsp; you build an amp with two inputs and a high gain. then hook it up so it &quot;amplifies the difference of the inputs by a high gain&quot;.&nbsp; then you take the output from the amp and hook it up to the input.&nbsp; basically the output would never be more then 1/gain away from the input voltage.further, the power dissipated by the amp is dominated by the voltage across the output transistors and the current through them.&nbsp; if you have a power supply voltage of 30V, and an output voltage of 20V, then you have 10V across the transistor.&nbsp; if you have 5A of output current (for a 4ohm load) you will have 10V * 5A = 50W of power loss at this moment.&nbsp; this power loss spec is based only upon the output signal, and not the input signal -- so long as the output signal is the same, it will not matter what input caused it.</blockquote>

[QUOTE="thch, post: 1483995, member: 562032"] common misconception. the input siganl from the RCA's is a control signal -- it provides insignifigant energy for the amp to actually do anything. with transistors it is easy to get a voltage gain of over 10,000. in fact that's how amps end up working. you build an amp with two inputs and a high gain. then hook it up so it "amplifies the difference of the inputs by a high gain". then you take the output from the amp and hook it up to the input. basically the output would never be more then 1/gain away from the input voltage. further, the power dissipated by the amp is dominated by the voltage across the output transistors and the current through them. if you have a power supply voltage of 30V, and an output voltage of 20V, then you have 10V across the transistor. if you have 5A of output current (for a 4ohm load) you will have 10V * 5A = 50W of power loss at this moment. this power loss spec is based only upon the output signal, and not the input signal -- so long as the output signal is the same, it will not matter what input caused it. [/QUOTE]

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