Reply to thread

Message

<blockquote data-quote="ny96j30" data-source="post: 343396" data-attributes="member: 551278">I actually tried to delete it, but couldn&#039;t figure out how.&nbsp; What I need is for someone to direct me to a quick tutorial on amps (is there one on this site?).Here&#039;s what I need to know:1) What is the mathmatical formula for determing how much power you get from a bridged channel?&nbsp; The PPI is 85x4 @ 4 ohms, what will I get out of 3 channels: 85x2 @ 4, and ? x1 @ ?2) I need to learn about impedance and wiring (i.e. parallel, sequence..).&nbsp; I know that power received and impedance are inversely proportional, I assume that to mean that any 4 ohm measure of RMS is a quarter of the actual output - if the device it was run to offered no resistance. So is there any way to wire a sub to the bridged channel at 2 ohms and double its power?Clearly I have alot to learn, any help would be appreciated, or direction to any place I can learn.&nbsp; Thanks</blockquote>

[QUOTE="ny96j30, post: 343396, member: 551278"] I actually tried to delete it, but couldn't figure out how. What I need is for someone to direct me to a quick tutorial on amps (is there one on this site?). Here's what I need to know: 1) What is the mathmatical formula for determing how much power you get from a bridged channel? The PPI is 85x4 @ 4 ohms, what will I get out of 3 channels: 85x2 @ 4, and ? x1 @ ? 2) I need to learn about impedance and wiring (i.e. parallel, sequence..). I know that power received and impedance are inversely proportional, I assume that to mean that any 4 ohm measure of RMS is a quarter of the actual output - if the device it was run to offered no resistance. So is there any way to wire a sub to the bridged channel at 2 ohms and double its power? Clearly I have alot to learn, any help would be appreciated, or direction to any place I can learn. Thanks [/QUOTE]

Verification