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Miscellaneous Automotive
Car Performance & Repair
Power & Torque
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<blockquote data-quote="marleyskater420" data-source="post: 844493" data-attributes="member: 549075"><p>In a 4 cylinder engine, 1 cylinder will be in 1 of the given cycles at any given time. This means that 1 cylinder will provide torque every ¼ revolution. In an 8 cylinder engine, 2 cylinders will be in 1 of the given cycles at any given time. This means that 2 cylinders will provide torque every ¼ revolution which means that the torque from each of those two cylinders is combined to turn the crankshaft. So, in our 4 cylinder engine, we’re making 209.44 lb-ft of Torque while we’re making 418.88 lb-ft of Torque in the V8.</p><p></p><p>I dont get this.. if the 4 cyl makes 209tq every power stroke, then it would make 418 in a revolution, because it has 2 power strokes every revolution.</p><p></p><p>You are saying that a V8 would fire all 8 cylinders in a revolution, but this isn't true.</p><p></p><p>1 cyl in a 4cyl doesnt fire every 1/4 rev, I dont understand this.</p><p></p><p>360/number of cylinders *2 =how many degrees it fires in crankshaft rotation</p><p></p><p>360/4 *2=180. A 4cyl will fire every 180degrees, not every 90. A V8 wont fire 2 cyls at the same time, so 2 wouldnt be every 1/4 rev.</p><p></p><p>a 400hp 4cyl will fire 2 times in a revolution, and a 8cyl 400hp car will fire 4 times in a rev, both will produce 200hp, because in the 4cyl each cyl produces 100hp, and in the 8cyl each produces 50hp. So if each cyl in a car makes 209hp,and the car is a 4cyl, it would make 418hp per revolution,not 209.</p><p></p><p>Okay, so the engine produces Torque, but how do we transmit that Torque to the ground ? Well, on the way to the ground, it has to pass through the transmission, differential, and wheels to get to the ground. Let’s say we have a first gear ratio of 3:1, a final drive (differential) ratio of 4:1, and a set of 195/60/15 drive wheels. Okay, so our engine is churning out 209.44 lb-ft at the crank in our 4 cylinder engine and the first gear has a Radius 3 times greater than that of the crankshaft’s, so we get 209.44/X = Y/3X … If we multiply each side by 3X, we get 209.44*3 = 628.32 lb-ft of Torque … So the gear pretty much acted as a Torque multiplier. Now we pass down the driveshaft to the differential where we have a ratio of 4:1 or 4 times greater Radius than First gear, so we get 628.32/X = Y/4X … 628.32*4 = 2513.28 lb-ft of Torque … Again, it acted as a multiplier. Now we turn to the wheels, where we actually have a known Radius and a known Torque, but we don’t know the Force. To get the diameter of the wheel, we take the rim size (15”) and add the height of the tire (2*195*0.6/25.4) = 24.2126” or a Radius of 12.1063” … 1 foot = 12” and 2513.28 lb-ft is equal to applying 2513.28 lbs of Force to a 1 foot Radius or X Force applied to a 12.1063/12 Radius … So we get 2513.28*1 = X*12.1063/12 … So we multiply each side by 12/12.1063 and get X = 2513.28*12/12.1063 = 2491.212 lbs of Force … So we finally translated our engine’s torque into a force at the wheels. So this means that Torque is all that matters, right ? Wrong …</p><p></p><p>Can you explain this a little more for us stupid people</p></blockquote><p></p>
[QUOTE="marleyskater420, post: 844493, member: 549075"] In a 4 cylinder engine, 1 cylinder will be in 1 of the given cycles at any given time. This means that 1 cylinder will provide torque every ¼ revolution. In an 8 cylinder engine, 2 cylinders will be in 1 of the given cycles at any given time. This means that 2 cylinders will provide torque every ¼ revolution which means that the torque from each of those two cylinders is combined to turn the crankshaft. So, in our 4 cylinder engine, we’re making 209.44 lb-ft of Torque while we’re making 418.88 lb-ft of Torque in the V8. I dont get this.. if the 4 cyl makes 209tq every power stroke, then it would make 418 in a revolution, because it has 2 power strokes every revolution. You are saying that a V8 would fire all 8 cylinders in a revolution, but this isn't true. 1 cyl in a 4cyl doesnt fire every 1/4 rev, I dont understand this. 360/number of cylinders *2 =how many degrees it fires in crankshaft rotation 360/4 *2=180. A 4cyl will fire every 180degrees, not every 90. A V8 wont fire 2 cyls at the same time, so 2 wouldnt be every 1/4 rev. a 400hp 4cyl will fire 2 times in a revolution, and a 8cyl 400hp car will fire 4 times in a rev, both will produce 200hp, because in the 4cyl each cyl produces 100hp, and in the 8cyl each produces 50hp. So if each cyl in a car makes 209hp,and the car is a 4cyl, it would make 418hp per revolution,not 209. Okay, so the engine produces Torque, but how do we transmit that Torque to the ground ? Well, on the way to the ground, it has to pass through the transmission, differential, and wheels to get to the ground. Let’s say we have a first gear ratio of 3:1, a final drive (differential) ratio of 4:1, and a set of 195/60/15 drive wheels. Okay, so our engine is churning out 209.44 lb-ft at the crank in our 4 cylinder engine and the first gear has a Radius 3 times greater than that of the crankshaft’s, so we get 209.44/X = Y/3X … If we multiply each side by 3X, we get 209.44*3 = 628.32 lb-ft of Torque … So the gear pretty much acted as a Torque multiplier. Now we pass down the driveshaft to the differential where we have a ratio of 4:1 or 4 times greater Radius than First gear, so we get 628.32/X = Y/4X … 628.32*4 = 2513.28 lb-ft of Torque … Again, it acted as a multiplier. Now we turn to the wheels, where we actually have a known Radius and a known Torque, but we don’t know the Force. To get the diameter of the wheel, we take the rim size (15”) and add the height of the tire (2*195*0.6/25.4) = 24.2126” or a Radius of 12.1063” … 1 foot = 12” and 2513.28 lb-ft is equal to applying 2513.28 lbs of Force to a 1 foot Radius or X Force applied to a 12.1063/12 Radius … So we get 2513.28*1 = X*12.1063/12 … So we multiply each side by 12/12.1063 and get X = 2513.28*12/12.1063 = 2491.212 lbs of Force … So we finally translated our engine’s torque into a force at the wheels. So this means that Torque is all that matters, right ? Wrong … Can you explain this a little more for us stupid people [/QUOTE]
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