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OK not sure myself but..lol
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<blockquote data-quote="squeak9798" data-source="post: 1404042" data-attributes="member: 555320"><p>You are referring to effective radiating area....or "Sd" in the T/S parameters.</p><p></p><p>And you are correct, those large wide-roll surrounds do eat up cone area, decreasing the volume of air the subwoofer can displace (Vd, which is essentially Xmax * Sd), decreasing potential output. If you take two exact same drivers, one with a wide-roll surround (and hence less Sd), and the other has a "normal" surround....the one with the normal surround will have more potential output because of it's increase in effecitve radiating area.</p><p></p><p>Sd takes into account 1/3 (or 1/2 depending on the company) of the surround when calculating effective radiating area. The actual calculation for Sd is;</p><p></p><p>Sd = (3.1416 * D^2)/4</p><p></p><p>where D is the diameter of the cone plus 1/3 (or 1/2) of the surround at both ends of the measurement.</p></blockquote><p></p>
[QUOTE="squeak9798, post: 1404042, member: 555320"] You are referring to effective radiating area....or "Sd" in the T/S parameters. And you are correct, those large wide-roll surrounds do eat up cone area, decreasing the volume of air the subwoofer can displace (Vd, which is essentially Xmax * Sd), decreasing potential output. If you take two exact same drivers, one with a wide-roll surround (and hence less Sd), and the other has a "normal" surround....the one with the normal surround will have more potential output because of it's increase in effecitve radiating area. Sd takes into account 1/3 (or 1/2 depending on the company) of the surround when calculating effective radiating area. The actual calculation for Sd is; Sd = (3.1416 * D^2)/4 where D is the diameter of the cone plus 1/3 (or 1/2) of the surround at both ends of the measurement. [/QUOTE]
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