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ohms, watts, bridging, confused?????
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<blockquote data-quote="IASCA pro 301-6" data-source="post: 5579" data-attributes="member: 541179"><p>the reason that two four ohm subs, when connected to an amp with a load of two ohms creates a one ohm load is because when bridging an amp, it "sees" half of the load it is given. This is due to the topography of the design of the amp. There are amps on the market that both do this as well as a number of new amps that compensate for the ohm load and they do not see this half-load. You need to be aware of the specs on the amp you are looking at. If it is spec'd to handle a two ohm load, do not give it more than two ohms...its that easy.</p><p></p><p>As for the formula to calculate ohm load:</p><p></p><p>1 devided by the the sum of 1 devided by r1 plus 1 devided r2 plus 1 devided by rn. This sound real confusing in print, but it makes more sence if you see it. To answer your question: three 4 ohm subs in parellel is 1.33 ohms.</p><p></p><p>Todd</p></blockquote><p></p>
[QUOTE="IASCA pro 301-6, post: 5579, member: 541179"] the reason that two four ohm subs, when connected to an amp with a load of two ohms creates a one ohm load is because when bridging an amp, it "sees" half of the load it is given. This is due to the topography of the design of the amp. There are amps on the market that both do this as well as a number of new amps that compensate for the ohm load and they do not see this half-load. You need to be aware of the specs on the amp you are looking at. If it is spec'd to handle a two ohm load, do not give it more than two ohms...its that easy. As for the formula to calculate ohm load: 1 devided by the the sum of 1 devided by r1 plus 1 devided r2 plus 1 devided by rn. This sound real confusing in print, but it makes more sence if you see it. To answer your question: three 4 ohm subs in parellel is 1.33 ohms. Todd [/QUOTE]
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ohms, watts, bridging, confused?????
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