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<blockquote data-quote="maylar" data-source="post: 210806" data-attributes="member: 541144">You would be correct. Here&#039;s the way it&#039;s supposed to work:In the simplest case, you have an inductor in series with the woofer, and a capacitor in series with the tweeter. At low frequencies, the capacitor is high impedance and the inductor is low impedance. The tweeter is basically out of the circuit. The only thing the amp sees is the woofer&#039;s 4 ohms. At high frequncies, it&#039;s just the opposite... the inductor is high impedancce and the cap is low. So the woofer is out of the circuit and the amp only sees the tweeter&#039;s 4 ohms.There are 2 crossover points... the frequencies where the inductor and the cap are 4 ohms (the 3 dB points). If the crossover frequency is the same for both, then you have 4 ohms at the crossover point (4 ohms woofer + 4 ohms inductor in parralel with 4 ohns tweeter + 4 ohms capacitor). If the crossover points are different, the impedance at those frequencies gets more difficult to calculate.Again, if the crossover points are the same then you only have one element (woofer or tweeter) that appears as the load to the amp at any given frequency. That means you&#039;ll have 4 ohms.Calculating the values of components for the crossovers, you use the impedance of the driver. You&#039;re basically constructing hipass or lowpass filters for the driver.</blockquote>

[QUOTE="maylar, post: 210806, member: 541144"] You would be correct. Here's the way it's supposed to work: In the simplest case, you have an inductor in series with the woofer, and a capacitor in series with the tweeter. At low frequencies, the capacitor is high impedance and the inductor is low impedance. The tweeter is basically out of the circuit. The only thing the amp sees is the woofer's 4 ohms. At high frequncies, it's just the opposite... the inductor is high impedancce and the cap is low. So the woofer is out of the circuit and the amp only sees the tweeter's 4 ohms. There are 2 crossover points... the frequencies where the inductor and the cap are 4 ohms (the 3 dB points). If the crossover frequency is the same for both, then you have 4 ohms at the crossover point (4 ohms woofer + 4 ohms inductor in parralel with 4 ohns tweeter + 4 ohms capacitor). If the crossover points are different, the impedance at those frequencies gets more difficult to calculate. Again, if the crossover points are the same then you only have one element (woofer or tweeter) that appears as the load to the amp at any given frequency. That means you'll have 4 ohms. Calculating the values of components for the crossovers, you use the impedance of the driver. You're basically constructing hipass or lowpass filters for the driver. [/QUOTE]

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