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<blockquote data-quote="Jeffdachef" data-source="post: 8384678" data-attributes="member: 650438"><p>dual 0.7 wired in series/parallel will give you 1.4 ohms. Since there is two of them, you divide it by two. So you will end up with 0.7 ohms final impedance with two in series/parallel.</p><p></p><p>If you wire straight up series, then it would be 5.6 ohms for a pair.</p><p></p><p>If you wire straight up parallel, then it would be 0.35 ohms divided by two so 0.175 ohms final for two wired parallel.</p><p></p><p>If you are doing 4 of them, you can do a parallel/series(not to be confused with series/parallel) configuration ending up with 1.4 ohms.</p></blockquote><p></p>
[QUOTE="Jeffdachef, post: 8384678, member: 650438"] dual 0.7 wired in series/parallel will give you 1.4 ohms. Since there is two of them, you divide it by two. So you will end up with 0.7 ohms final impedance with two in series/parallel. If you wire straight up series, then it would be 5.6 ohms for a pair. If you wire straight up parallel, then it would be 0.35 ohms divided by two so 0.175 ohms final for two wired parallel. If you are doing 4 of them, you can do a parallel/series(not to be confused with series/parallel) configuration ending up with 1.4 ohms. [/QUOTE]
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