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need box help for 2 18s
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<blockquote data-quote="walled01alero" data-source="post: 6926396" data-attributes="member: 622835"><p>you didn't say anything about a flared port. and btw the "flare" at the end of the port doesn't actually belong the the port. the volume of air inside the flared sections dont count towards displacement. and when finding port area you have to look at the narrowest part of the port, because it's the narrowest part the determines the restriction in port air velocity. if you're measuring port area at the widest part of the flare just forget that and use the diameter of the tube you have.</p><p></p><p>8" inner diameter port = 3.14(4in.^2) = 50.24 INCHES SQUARED. look at the units and see if they make sense.. (p.s. 3.14 (or pi) is a dimentionless ratio)</p></blockquote><p></p>
[QUOTE="walled01alero, post: 6926396, member: 622835"] you didn't say anything about a flared port. and btw the "flare" at the end of the port doesn't actually belong the the port. the volume of air inside the flared sections dont count towards displacement. and when finding port area you have to look at the narrowest part of the port, because it's the narrowest part the determines the restriction in port air velocity. if you're measuring port area at the widest part of the flare just forget that and use the diameter of the tube you have. 8" inner diameter port = 3.14(4in.^2) = 50.24 INCHES SQUARED. look at the units and see if they make sense.. (p.s. 3.14 (or pi) is a dimentionless ratio) [/QUOTE]
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