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More Power out of my Kenwood?
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<blockquote data-quote="adblink182" data-source="post: 719442" data-attributes="member: 559283"><p>ok, i need to make sure I have this right before I ask this question.....if I'm wrong then dont even bother to keep reading //content.invisioncic.com/y282845/emoticons/crazy.gif.c13912c32de98515d3142759a824dae7.gif</p><p></p><p>Ok lets see if I have this right.....I currently have a <a href="http://www.kenwood.ca/kwcgi/kww001?cono=01&amp;lgid=E&amp;item=KAC-8101D" target="_blank">Kenwood KAC-8101D</a> mono amp....and I have a single <a href="http://www.cerwinvega.com/products/mobileaudio/hed/hed12.html" target="_blank">Cerwin Vega HED 12"</a> sub...</p><p></p><p>now running one sub, the amp is putting out "200W x 1 Continous Power Output (4 Ohms)" according to their site...</p><p></p><p>now as I understand it, if I added a second identical sub...the ohms would now be 2.....which means that amp would be doing "400W x 1 Continous Power Output (2 Ohms)"</p><p></p><p>now I have no intentions of adding another sub (want to use the money for other things).....</p><p></p><p>now my question is, instead of buying another sub, can't I buy some type of 2 ohm resister and just wire that in?.....because if I do, the amp would be doing...400W x 1....hell what about dropping it to 1ohm so the amp is putting out 500W</p><p></p><p>like there must be away to make more resistance to get more power not just by adding another sub?</p><p></p><p>is what I'm saying at all correct, or am I just dancing by myself out in left field?</p></blockquote><p></p>
[QUOTE="adblink182, post: 719442, member: 559283"] ok, i need to make sure I have this right before I ask this question.....if I'm wrong then dont even bother to keep reading [IMG]//content.invisioncic.com/y282845/emoticons/crazy.gif.c13912c32de98515d3142759a824dae7.gif[/IMG] Ok lets see if I have this right.....I currently have a [URL="http://www.kenwood.ca/kwcgi/kww001?cono=01&lgid=E&item=KAC-8101D"]Kenwood KAC-8101D[/URL] mono amp....and I have a single [URL="http://www.cerwinvega.com/products/mobileaudio/hed/hed12.html"]Cerwin Vega HED 12"[/URL] sub... now running one sub, the amp is putting out "200W x 1 Continous Power Output (4 Ohms)" according to their site... now as I understand it, if I added a second identical sub...the ohms would now be 2.....which means that amp would be doing "400W x 1 Continous Power Output (2 Ohms)" now I have no intentions of adding another sub (want to use the money for other things)..... now my question is, instead of buying another sub, can't I buy some type of 2 ohm resister and just wire that in?.....because if I do, the amp would be doing...400W x 1....hell what about dropping it to 1ohm so the amp is putting out 500W like there must be away to make more resistance to get more power not just by adding another sub? is what I'm saying at all correct, or am I just dancing by myself out in left field? [/QUOTE]
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