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<blockquote data-quote="Immacomputer" data-source="post: 5151772" data-attributes="member: 570419">That&#039;s not really true. In a ported system, there will be two different spikes. Their relative peaks will be determined by the tuning frequency. Their distance away from the tuning frequency (in Hz) will be dependent on enclosure volume. The smaller the box, the further away the spikes occur from the tuning frequency and the larger the box, the closer they are to each other and the tuning frequency.It makes sense if you think about it. The impedance spikes are due to system resonances. If you make a box larger, or lower the spring force, resonance will happen at a lower frequency. Think about IB systems too. In a first order system like IB, there is only one impedance spike that will occur around the Fs of the driver. If you take a ported enclosure and make it infinitely&nbsp; large, you will have an IB system with only one resonance (port tuning) as the two peaks will converge.</blockquote>

[QUOTE="Immacomputer, post: 5151772, member: 570419"] That's not really true. In a ported system, there will be two different spikes. Their relative peaks will be determined by the tuning frequency. Their distance away from the tuning frequency (in Hz) will be dependent on enclosure volume. The smaller the box, the further away the spikes occur from the tuning frequency and the larger the box, the closer they are to each other and the tuning frequency. It makes sense if you think about it. The impedance spikes are due to system resonances. If you make a box larger, or lower the spring force, resonance will happen at a lower frequency. Think about IB systems too. In a first order system like IB, there is only one impedance spike that will occur around the Fs of the driver. If you take a ported enclosure and make it infinitely large, you will have an IB system with only one resonance (port tuning) as the two peaks will converge. [/QUOTE]

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