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<blockquote data-quote="jrz126" data-source="post: 764747" data-attributes="member: 556466">It&#039;s good practice to wire in a resistor though.And you dont install the resistor to cut the voltage down necessarily, you use it to regulate current. Most LED&#039;s are designed to handle a constant 20mA. You use ohms law,R=V(at resistor)/I. The voltage at the resistor is Battery voltage-forward voltage of LED.So if you have a LED with a forward voltage of 3.2V, it would be (14.4-3.2)/.020A =560 ohms. or if you had 2 leds, 14.4-3.2-3.2/.020 = 400 ohms.and while we are showing off LED projects...<img src="http://memimage.cardomain.net/member_images/3/web/435000-435999/435572_107_full.jpg" alt="" class="fr-fic fr-dii fr-draggable " style="" />The backside...<img src="http://memimage.cardomain.net/member_images/3/web/435000-435999/435572_137_full.jpg" alt="" class="fr-fic fr-dii fr-draggable " style="" />one of 2 circuit boards to handle the high currentand the pic in my sig shows the final product...with an added effect from a fog machine...</blockquote>

[QUOTE="jrz126, post: 764747, member: 556466"] It's good practice to wire in a resistor though. And you dont install the resistor to cut the voltage down necessarily, you use it to regulate current. Most LED's are designed to handle a constant 20mA. You use ohms law, R=V(at resistor)/I. The voltage at the resistor is Battery voltage-forward voltage of LED. So if you have a LED with a forward voltage of 3.2V, it would be (14.4-3.2)/.020A =560 ohms. or if you had 2 leds, 14.4-3.2-3.2/.020 = 400 ohms. and while we are showing off LED projects... [IMG]http://memimage.cardomain.net/member_images/3/web/435000-435999/435572_107_full.jpg[/IMG] The backside... [IMG]http://memimage.cardomain.net/member_images/3/web/435000-435999/435572_137_full.jpg[/IMG] one of 2 circuit boards to handle the high current and the pic in my sig shows the final product...with an added effect from a fog machine... [/QUOTE]

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