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<blockquote data-quote="helotaxi" data-source="post: 1610145" data-attributes="member: 550915">How did he define &quot;equivalent actual power?&quot;&nbsp; RMS?&nbsp; The RMS of a Sine wave is .707 of the peak voltage time the current.&nbsp; The RMS of a fully clipped signal is the peak voltage times the current.&nbsp; The rated power of the clipped amp is somewhat less than the output at full clipping.So as an example, if you had a sub rated for 600W and were running it with a 500W amp.&nbsp; The enclosure will allow the sub to handle the power, so mechanical power-handling is not an issue.&nbsp; You have a 500W amp.&nbsp; Can you blow the sub?&nbsp; Fully clip that amp and if the sub rating is truly a limit and not conservative estimate, that sub could be short of this world.There are some other problems here as well.&nbsp; With impedence, there is impedence rise.&nbsp; Impedence requires AC.&nbsp; With a fully clipped signal, there is no longer an impedence, but rather Re becomes the driver resistance at the peaks.&nbsp; Now you have more voltage than normal through less resistance than normal.&nbsp; Now if you are just measuring actual power applied this is accounted for.&nbsp; Also consider that during these periods of high power application, there is close to zero movement of the cone.I didn&#039;t see the test myself.&nbsp; A few questions about it.&nbsp; What was the quality of the driver used?&nbsp; Was it a quality unit with conservative power rating or was it a budget driver?&nbsp; How much power was used in relation to the rated power of the sub?&nbsp; If the power applied was nowhere near the real world power handling of the driver then the test is only of marginal validity.&nbsp; I fully agree that if you take an L7 or a XXX or something of that nature and run it on a fully clipped 500W amp you probably don&#039;t have much to worry about, but if you take a sub designed for a lower power you will need to be more careful with the gains, even with a relatively small amp.</blockquote>

[QUOTE="helotaxi, post: 1610145, member: 550915"] How did he define "equivalent actual power?" RMS? The RMS of a Sine wave is .707 of the peak voltage time the current. The RMS of a fully clipped signal is the peak voltage times the current. The rated power of the clipped amp is somewhat less than the output at full clipping. So as an example, if you had a sub rated for 600W and were running it with a 500W amp. The enclosure will allow the sub to handle the power, so mechanical power-handling is not an issue. You have a 500W amp. Can you blow the sub? Fully clip that amp and if the sub rating is truly a limit and not conservative estimate, that sub could be short of this world. There are some other problems here as well. With impedence, there is impedence rise. Impedence requires AC. With a fully clipped signal, there is no longer an impedence, but rather Re becomes the driver resistance at the peaks. Now you have more voltage than normal through less resistance than normal. Now if you are just measuring actual power applied this is accounted for. Also consider that during these periods of high power application, there is close to zero movement of the cone. I didn't see the test myself. A few questions about it. What was the quality of the driver used? Was it a quality unit with conservative power rating or was it a budget driver? How much power was used in relation to the rated power of the sub? If the power applied was nowhere near the real world power handling of the driver then the test is only of marginal validity. I fully agree that if you take an L7 or a XXX or something of that nature and run it on a fully clipped 500W amp you probably don't have much to worry about, but if you take a sub designed for a lower power you will need to be more careful with the gains, even with a relatively small amp. [/QUOTE]

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