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<blockquote data-quote="TaylorFade" data-source="post: 7715290" data-attributes="member: 618111"><p>15" = ~ 175sq in of cone.</p><p></p><p>12" = ~ 112sq in of cone.</p><p></p><p>That's not quite half, but all things being equal, you will lose output. As has been alluded to, doubling of cone area or power is a theoretical +3db gain, but a "percieved" twice as loud is more like +6db. 1-2db would be barely noticeable, IMO.</p><p></p><p>I don't know what your situations is, but most 12's wil be ~ 2 cubes of box. You can get a pair of 10's in or around there and lose barely any cone if that's a viable option for you.</p></blockquote><p></p>
[QUOTE="TaylorFade, post: 7715290, member: 618111"] 15" = ~ 175sq in of cone. 12" = ~ 112sq in of cone. That's not quite half, but all things being equal, you will lose output. As has been alluded to, doubling of cone area or power is a theoretical +3db gain, but a "percieved" twice as loud is more like +6db. 1-2db would be barely noticeable, IMO. I don't know what your situations is, but most 12's wil be ~ 2 cubes of box. You can get a pair of 10's in or around there and lose barely any cone if that's a viable option for you. [/QUOTE]
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