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Impedance question on specific amp
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<blockquote data-quote="squeak9798" data-source="post: 3709102" data-attributes="member: 555320"><p>Yes, it does care.</p><p></p><p>Why?</p><p></p><p>Each channel is only stable down to 2ohms. "The amp" isn't stable to 2ohms. <em>Each channel</em> is stable down to 2ohms.</p><p></p><p>What happens when you bridge an amplifier ? Well, in effect, when you bridge a 2-channel amplifier each channel will "see" half the load.</p><p></p><p>So if you bridge the amplifier into a 4ohm load, <em>each channel</em> would effectively "see" a 2ohm load. This is fine and dandy because each channel can support a 2ohm load.</p><p></p><p>But then what happens when you bridge the amplifier to a 2ohm load ? Well, each channel would effectively see a 1ohm load. Each channel can not support a 1ohm load. It's below their stable operating range. So you now run the risk of damaging the amplifier, or if sufficient protection circuits are built into the amplifier it will likely kick into protection.</p></blockquote><p></p>
[QUOTE="squeak9798, post: 3709102, member: 555320"] Yes, it does care. Why? Each channel is only stable down to 2ohms. "The amp" isn't stable to 2ohms. [I]Each channel[/I] is stable down to 2ohms. What happens when you bridge an amplifier ? Well, in effect, when you bridge a 2-channel amplifier each channel will "see" half the load. So if you bridge the amplifier into a 4ohm load, [I]each channel[/I] would effectively "see" a 2ohm load. This is fine and dandy because each channel can support a 2ohm load. But then what happens when you bridge the amplifier to a 2ohm load ? Well, each channel would effectively see a 1ohm load. Each channel can not support a 1ohm load. It's below their stable operating range. So you now run the risk of damaging the amplifier, or if sufficient protection circuits are built into the amplifier it will likely kick into protection. [/QUOTE]
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