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how to run a 2nd bat.
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<blockquote data-quote="Thnking" data-source="post: 2485312" data-attributes="member: 571105"><p><a href="http://www.treehugger.com/files/2006/03/eestor_capacito_1.php" target="_blank">http://www.treehugger.com/files/2006/03/eestor_capacito_1.php</a></p><p></p><p><a href="http://www.engr.wisc.edu/wiscengr/feb06/Lithium%20Ion.shtml" target="_blank">http://www.engr.wisc.edu/wiscengr/feb06/Lithium%20Ion.shtml</a></p><p></p><p><a href="http://www.thetech.org/about/press/index.php?id=134" target="_blank">http://www.thetech.org/about/press/index.php?id=134</a></p><p></p><p>Your article points to the same occurrence happening, of course it’s not happening overnight.</p><p></p><p>If the wire is sized properly, there isn’t going to be a 1V drop. Even the lowest standard for wire selection, without using ampacity, is .5V.</p><p></p><p>The alternator is reacting to changing load, the output is going to be varying. And the reaction to that variation is going to be under 10ms. I know it’s difficult to face reality, but it is what it is.</p><p></p><p>How does this relate to anything… If there is no dimming and no related significant voltage drops no electrical upgrades need to be done.</p><p></p><p>How am I supposed to know?</p><p></p><p>If you think that a .5V increase in supply voltage for a given load and gains set point has somehow stopped an amplifier from overheating, you’re crazy. V*A=P. Voltage increasing doesn’t mean less heat. You need a basic high school physics class again, even though below you say you understand it…</p><p></p><p>I said was that there is protection for under voltage and over voltage. Amplifier designers have limiting factors when selecting components, like Safe Operating Areas (SOA) for transistors to prevent secondary breakdown. They are current relative to voltage, or vice versa, operating ranges for transistors. Protection circuitry is in place to keep the components operating as they were intended to and to prevent instability.</p><p></p><p>If you see an amplifier which doesn’t have protection circuitry for its output stage or VA stage, show me I’d be absolutely amazed.</p><p></p><p>Where in the amplifier does efficiency drop when supply voltage drops…I bet you can’t tell me. Why? Because it doesn’t necessarily drop, that’s mainly a topology issue.</p><p></p><p>The fact remains that excess power over heats the amplifier, not a decrease in voltage. The two don’t go hand in hand. If the gains are set right, then a decrease in voltage isn’t going to do anything to the amplifier. And if the gains are set too low (input too high) an increase in voltage, a decrease in voltage, or the voltage remaining the same will damage it.</p></blockquote><p></p>
[QUOTE="Thnking, post: 2485312, member: 571105"] [URL="http://www.treehugger.com/files/2006/03/eestor_capacito_1.php"]http://www.treehugger.com/files/2006/03/eestor_capacito_1.php[/URL] [URL="http://www.engr.wisc.edu/wiscengr/feb06/Lithium%20Ion.shtml"]http://www.engr.wisc.edu/wiscengr/feb06/Lithium%20Ion.shtml[/URL] [URL="http://www.thetech.org/about/press/index.php?id=134"]http://www.thetech.org/about/press/index.php?id=134[/URL] Your article points to the same occurrence happening, of course it’s not happening overnight. If the wire is sized properly, there isn’t going to be a 1V drop. Even the lowest standard for wire selection, without using ampacity, is .5V. The alternator is reacting to changing load, the output is going to be varying. And the reaction to that variation is going to be under 10ms. I know it’s difficult to face reality, but it is what it is. How does this relate to anything… If there is no dimming and no related significant voltage drops no electrical upgrades need to be done. How am I supposed to know? If you think that a .5V increase in supply voltage for a given load and gains set point has somehow stopped an amplifier from overheating, you’re crazy. V*A=P. Voltage increasing doesn’t mean less heat. You need a basic high school physics class again, even though below you say you understand it… I said was that there is protection for under voltage and over voltage. Amplifier designers have limiting factors when selecting components, like Safe Operating Areas (SOA) for transistors to prevent secondary breakdown. They are current relative to voltage, or vice versa, operating ranges for transistors. Protection circuitry is in place to keep the components operating as they were intended to and to prevent instability. If you see an amplifier which doesn’t have protection circuitry for its output stage or VA stage, show me I’d be absolutely amazed. Where in the amplifier does efficiency drop when supply voltage drops…I bet you can’t tell me. Why? Because it doesn’t necessarily drop, that’s mainly a topology issue. The fact remains that excess power over heats the amplifier, not a decrease in voltage. The two don’t go hand in hand. If the gains are set right, then a decrease in voltage isn’t going to do anything to the amplifier. And if the gains are set too low (input too high) an increase in voltage, a decrease in voltage, or the voltage remaining the same will damage it. [/QUOTE]
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