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Amplifiers
higher impedance easier on electric system?
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<blockquote data-quote="akheathen" data-source="post: 7851480" data-attributes="member: 629234"><p>what i am looking at is how the power is passed through the torroid(s), where the greatest majority of efficiency is determined. at lower power levels, a lot of the field enters in and around the core and a lower amount is sent through the secondaries, as they only need so much. the use in the secondaries lowers resistance effect the secondaries have on the total inductance. <em>dynamic</em> headroom is a big part to do with the rail storage caps and impedance drop below the mean topology. however, i was just answering the simple question of efficiency. iirc, the 2 amps were hypothetical amps, so i went with what is most likely and common traits, which is not usually .5 stable, and even if it is .5, it would probably still reach the most efficiency at 1ohm, or 2ohm load. at lower imp. there is more strain and loss in the whole system.</p></blockquote><p></p>
[QUOTE="akheathen, post: 7851480, member: 629234"] what i am looking at is how the power is passed through the torroid(s), where the greatest majority of efficiency is determined. at lower power levels, a lot of the field enters in and around the core and a lower amount is sent through the secondaries, as they only need so much. the use in the secondaries lowers resistance effect the secondaries have on the total inductance. [I]dynamic[/I] headroom is a big part to do with the rail storage caps and impedance drop below the mean topology. however, i was just answering the simple question of efficiency. iirc, the 2 amps were hypothetical amps, so i went with what is most likely and common traits, which is not usually .5 stable, and even if it is .5, it would probably still reach the most efficiency at 1ohm, or 2ohm load. at lower imp. there is more strain and loss in the whole system. [/QUOTE]
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higher impedance easier on electric system?
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