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<blockquote data-quote="dinty01" data-source="post: 2628556" data-attributes="member: 567850"><p>hey, if I got it right, youll be around 4.39 square feet without port and sub displacement. I broke the box up into 3 parts, the 2 outside sections are the same dimensions, and then did the center as a 3rd box. for the 2 outside boxes it would 23x10x14 = 1.86 cubic feet per side, so 3.73 cuft for both sides, and then for the inside it is 6.75x12x14 = 0.66 cuft, total is 4.39 cuft. And if youre wondering where the 10 came from, the way I was taught it is easier to make the front of the box a square, so you take the top and bottom depths, add then together then divide by 2, in this case 8" and 12" added together get 20, divided by get 10", I then did this for the center box as well, with a dimension of 6.75" straight up and down, some will say this method is incorrect but its worked for me several times without problems. If you try using those dimensions I posted above, you should be able to use a box calculator to double check my math, I think its right if I understand your drawings. If you have any questions feel free to post them, Hope this helps----Dinty</p></blockquote><p></p>
[QUOTE="dinty01, post: 2628556, member: 567850"] hey, if I got it right, youll be around 4.39 square feet without port and sub displacement. I broke the box up into 3 parts, the 2 outside sections are the same dimensions, and then did the center as a 3rd box. for the 2 outside boxes it would 23x10x14 = 1.86 cubic feet per side, so 3.73 cuft for both sides, and then for the inside it is 6.75x12x14 = 0.66 cuft, total is 4.39 cuft. And if youre wondering where the 10 came from, the way I was taught it is easier to make the front of the box a square, so you take the top and bottom depths, add then together then divide by 2, in this case 8" and 12" added together get 20, divided by get 10", I then did this for the center box as well, with a dimension of 6.75" straight up and down, some will say this method is incorrect but its worked for me several times without problems. If you try using those dimensions I posted above, you should be able to use a box calculator to double check my math, I think its right if I understand your drawings. If you have any questions feel free to post them, Hope this helps----Dinty [/QUOTE]
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