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Help setting gain on amp equation?
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<blockquote data-quote="Jepalan" data-source="post: 8171251" data-attributes="member: 655519"><p>Wrong. 4 x 4-ohm *single* voicecoil subs wired in *parallel* will be 1-ohm. 4 x 4ohm *single* voicecoil subs in *series* is 16-ohms.</p><p></p><p>BUT</p><p></p><p>The OP's sub is *DUAL* voicecoil. 4-ohms per VC. If he wires all the VCs in parallel he will have .5 ohm load. Let's just assume he has .5 ohms and answer his question.</p><p></p><p>Since each sub is wired to 2-ohms (2 x 4-ohm VCs in parallel), you are either putting 600 watts RMS into 2 ohms, or putting 2400RMS into .5 ohms.</p><p></p><p>So sqrt(600 x 2) = 34.64v, OR sqrt(2400 x 0.5) = 34.64v (same answer either way - which is a good thing)</p><p></p><p>---</p><p></p><p>You could also assume you are putting 300W into each 4-ohm VC and calc sqrt(300 x 4) = 34.64v</p></blockquote><p></p>
[QUOTE="Jepalan, post: 8171251, member: 655519"] Wrong. 4 x 4-ohm *single* voicecoil subs wired in *parallel* will be 1-ohm. 4 x 4ohm *single* voicecoil subs in *series* is 16-ohms. BUT The OP's sub is *DUAL* voicecoil. 4-ohms per VC. If he wires all the VCs in parallel he will have .5 ohm load. Let's just assume he has .5 ohms and answer his question. Since each sub is wired to 2-ohms (2 x 4-ohm VCs in parallel), you are either putting 600 watts RMS into 2 ohms, or putting 2400RMS into .5 ohms. So sqrt(600 x 2) = 34.64v, OR sqrt(2400 x 0.5) = 34.64v (same answer either way - which is a good thing) --- You could also assume you are putting 300W into each 4-ohm VC and calc sqrt(300 x 4) = 34.64v [/QUOTE]
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Help setting gain on amp equation?
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