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<blockquote data-quote="smoka" data-source="post: 6277447" data-attributes="member: 606721">Sorry, you guys are both misguided in measuring the resistance of the ground circuit. If there is no load, then the readings are useless (unless there is an obvious problem).(V)Voltage drop = (I)current running through the wire x ®the resistance of the wireSo if you have no load, you can falsely assume you have no resistance.Here is an example using this voltage drop calculator:<a href="http://www.stealth316.com/2-wire-resistance.htm" target="_blank">http://www.stealth316.com/2-wire-resistance.htm</a>1/0ga wire at 20&#039; (the example is using power wire since the chassis equivalent is near impossible to guess, but I&#039;ve heard that testing has shown that the avg chassis is near equivalent to 1/0 wire)If there is no load, (I&#039;ll assume the amp is only using 1a of current in standby)Voltage drop of 0.002 voltsIf there is a 250a load,Voltage drop of 0.5 voltsSo even if there was a major problem and the grounds were in a bad spot, say if we multiply the resistance by 10. You would barely notice the 0.02v drop but you would definitely run into problems with a 5v drop.See why you need to &#039;load&#039; the circuit to get correct results?</blockquote>

[QUOTE="smoka, post: 6277447, member: 606721"] Sorry, you guys are both misguided in measuring the resistance of the ground circuit. If there is no load, then the readings are useless (unless there is an obvious problem). (V)Voltage drop = (I)current running through the wire x ®the resistance of the wire So if you have no load, you can falsely assume you have no resistance. Here is an example using this voltage drop calculator: [URL="http://www.stealth316.com/2-wire-resistance.htm"]http://www.stealth316.com/2-wire-resistance.htm[/URL] 1/0ga wire at 20' (the example is using power wire since the chassis equivalent is near impossible to guess, but I've heard that testing has shown that the avg chassis is near equivalent to 1/0 wire) If there is no load, (I'll assume the amp is only using 1a of current in standby) Voltage drop of 0.002 volts If there is a 250a load, Voltage drop of 0.5 volts So even if there was a major problem and the grounds were in a bad spot, say if we multiply the resistance by 10. You would barely notice the 0.02v drop but you would definitely run into problems with a 5v drop. See why you need to 'load' the circuit to get correct results? [/QUOTE]

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