Reply to thread

Message

<blockquote data-quote="Castro" data-source="post: 3444827" data-attributes="member: 580765">hmmmso i dont add the wattage of the 2 subs?????but then if i was to run 1 sub only the the formula would look likev=sqrt(300*4) ---&amp;gt; 4ohm 1 sub onlythen i would get v = 34.64it would only make sense that you add the RMS wattage of the 2 subs and since they are both connected to the amp and because they are in parallel then the fromula would look likev = sqrt ((300+300)*2) ---&amp;gt; 2ohm resistance(parallel)v= 34.64if they were in sereis the formula would look likesqrt((300+300)*8)&nbsp; ---&amp;gt; 8ohm resistance (series)v=69.28which makes sense 69.28=2*34.64 to accomidate the voltage drop across the 2 4ohm coils (2subs) connected in seriessorry to sound arogant, i just really want to understand whats goin on</blockquote>

[QUOTE="Castro, post: 3444827, member: 580765"] hmmm so i dont add the wattage of the 2 subs????? but then if i was to run 1 sub only the the formula would look like v=sqrt(300*4) ---> 4ohm 1 sub only then i would get v = 34.64 it would only make sense that you add the RMS wattage of the 2 subs and since they are both connected to the amp and because they are in parallel then the fromula would look like v = sqrt ((300+300)*2) ---> 2ohm resistance(parallel) v= 34.64 if they were in sereis the formula would look like sqrt((300+300)*8) ---> 8ohm resistance (series) v=69.28 which makes sense 69.28=2*34.64 to accomidate the voltage drop across the 2 4ohm coils (2subs) connected in series sorry to sound arogant, i just really want to understand whats goin on [/QUOTE]

Verification