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<blockquote data-quote="audioholic" data-source="post: 4112253" data-attributes="member: 549629"><p>The whole idea of a stronger signal voltage is for noise rejection. If you 'max the amp gains' and adjust everything from your preamp, you have in effect diminished your signal voltage going back to your amplifier(s) to the minimum. Im sure you can see the problem with this.</p><p>Not exactly. Contrary to popular belief, an amplifier is always trying to amplify the exact same amount.</p><p>Imagine an amplifier as a man pushing a large boulder up a hill. The amount of work created (watts) is how fast the man pushes the rock up the hill. The man (the amplifer) is always pushing with the same amount of force.</p><p></p><p>Now lets change the size of the rock, it is now double the original size. This is the same as doubling the impedance shown to the amplifier. When you double impedance, output power halves, and people think the amplifier is pushing half as hard. Its not, its pushing the rock with the same force. But work created (speed of rock being pushed up the hill) is halved because the rock size (impedance) is now doubled.</p><p></p><p>This shows that no matter the impedance placed on the amplifier, it is still amplifying (pushing) the same amount. Now lets discuss when you turn the volume up and down.... signal strength.</p><p></p><p>When you turn your h/u's volume up, amplifier output goes up. Again the amplifier is pushing with the same force, but as you turn up the volume you increase signal voltage, thus the amplifier has more voltage to amplify. Same pushing force (amplification) but higher starting voltage means higher output voltage (system volume increases).</p><p></p><p>So as you can see, an amplifier is always trying to 'amplify' with the same force, the only variable that change are merely the input signal strength, how much signal there is to amplify, and the resistance on the circuit (speaker impedance). To further emphasize my point, as I believe I said earlier in this thread... what happens when you change h/u's to one with a higher signal voltage? You adjust the gain down accordingly. You do not want a higher signal voltage so your amplifier has to 'amplify less' (implying it works less), its simply to increase the distance between the signal level and the noise level. No other reason, none.</p><p></p><p>Hope that clears things up.</p></blockquote><p></p>
[QUOTE="audioholic, post: 4112253, member: 549629"] The whole idea of a stronger signal voltage is for noise rejection. If you 'max the amp gains' and adjust everything from your preamp, you have in effect diminished your signal voltage going back to your amplifier(s) to the minimum. Im sure you can see the problem with this. Not exactly. Contrary to popular belief, an amplifier is always trying to amplify the exact same amount. Imagine an amplifier as a man pushing a large boulder up a hill. The amount of work created (watts) is how fast the man pushes the rock up the hill. The man (the amplifer) is always pushing with the same amount of force. Now lets change the size of the rock, it is now double the original size. This is the same as doubling the impedance shown to the amplifier. When you double impedance, output power halves, and people think the amplifier is pushing half as hard. Its not, its pushing the rock with the same force. But work created (speed of rock being pushed up the hill) is halved because the rock size (impedance) is now doubled. This shows that no matter the impedance placed on the amplifier, it is still amplifying (pushing) the same amount. Now lets discuss when you turn the volume up and down.... signal strength. When you turn your h/u's volume up, amplifier output goes up. Again the amplifier is pushing with the same force, but as you turn up the volume you increase signal voltage, thus the amplifier has more voltage to amplify. Same pushing force (amplification) but higher starting voltage means higher output voltage (system volume increases). So as you can see, an amplifier is always trying to 'amplify' with the same force, the only variable that change are merely the input signal strength, how much signal there is to amplify, and the resistance on the circuit (speaker impedance). To further emphasize my point, as I believe I said earlier in this thread... what happens when you change h/u's to one with a higher signal voltage? You adjust the gain down accordingly. You do not want a higher signal voltage so your amplifier has to 'amplify less' (implying it works less), its simply to increase the distance between the signal level and the noise level. No other reason, none. Hope that clears things up. [/QUOTE]
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