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<blockquote data-quote="Undisputed King" data-source="post: 5663456" data-attributes="member: 603818">Ok well for those ofyou who have taken a course in materials or something here it is:1. Diffusion:&nbsp; You have a tool made of low carbon (0.18% C) steel.&nbsp; You want to carburize the steel in order to harden the outside of the tool.&nbsp; In order to get the required hardness, you need to obtain a carbon content of 0.75% at a depth of 0.6 mm below the surface.  Design a carburizing treatment that would work well for this tool.&nbsp; Specify the temperature (in C), the surface carbon concentration (%), and the time required (in hours – or in minutes, if less than one hour) for this carburizing treatment.&nbsp; (I will check your values and make sure that they give the required carbon level at a depth of 0.6mm.)So you have the equation:<img src="http://www.industrialheating.com/IH/2000/12/Files/Images/7541.gif" alt="" class="fr-fic fr-dii fr-draggable " style="" />Now I cant solve for Cs because I also have the variable T. I chose D to be 1300 degrees C so for D I plug in 2.9x10^-10. Can anyone help?</blockquote>

[QUOTE="Undisputed King, post: 5663456, member: 603818"] Ok well for those ofyou who have taken a course in materials or something here it is: [I]1. Diffusion: You have a tool made of low carbon (0.18% C) steel. You want to carburize the steel in order to harden the outside of the tool. In order to get the required hardness, you need to obtain a carbon content of 0.75% at a depth of 0.6 mm below the surface.[/I] [I] [/I] [I] [/I] [I]Design a carburizing treatment that would work well for this tool. Specify the temperature (in C), the surface carbon concentration (%), and the time required (in hours – or in minutes, if less than one hour) for this carburizing treatment. (I will check your values and make sure that they give the required carbon level at a depth of 0.6mm.)[/I] So you have the equation: [IMG]http://www.industrialheating.com/IH/2000/12/Files/Images/7541.gif[/IMG] Now I cant solve for Cs because I also have the variable T. I chose D to be 1300 degrees C so for D I plug in 2.9x10^-10. Can anyone help? [/QUOTE]

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