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Message: <blockquote data-quote="Trixter" data-source="post: 3178441" data-attributes="member: 542668">using the formula in my sig i came up with....if using 6.0cu' net, port area of 45sq" and tuning of 34hz....port length is 12" add the end correction factor (if port shares a wall with the box) of 1.5" (1/2 the port's width) to get a 13.5" long port.the displacement of the port would be.....12.75 L (don't count the 3/4" for the face of the box since we're already using int. dims.) x 3.75 W (also the same with the port wall that shares a box side) x 15 H = 717.18 / 1728 = .42cu'so we're at 6.42cu for total net volume....add you sub disp. which you said was .123 now we have 6.54cu' box.using you max dims., now play with the numbers to get 6.54.</blockquote>

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