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<blockquote data-quote="ylpkm" data-source="post: 8315474" data-attributes="member: 655818">But for US amps, we use V^2, cause of its design, right? whereas some imports use a different design and gains cannot be set by the same voltmeter method right? (again just going from memory here). Sorry for going off track a little, and I dont exactly know how voltage and amperage from the speaker output on an amp correlate. But based on the calculator on bcae, it looks like the amperage is the voltage that is given divided by the impedance of the speaker .example: 8000 watts into 4 ohms=44.72 amp (current)178.89 voltsand 178/44=~4decrease impedance and current goes up, voltage drops.Again, maybe thats not how the volt to amp relationship works, just what i noticed using that calculator. If it does, voltage can be very high or rather low depending on impedance of the sub.and 2nd edit: now im confused, this makes no sense.</blockquote>

[QUOTE="ylpkm, post: 8315474, member: 655818"] But for US amps, we use V^2, cause of its design, right? whereas some imports use a different design and gains cannot be set by the same voltmeter method right? (again just going from memory here). Sorry for going off track a little, and I dont exactly know how voltage and amperage from the speaker output on an amp correlate. But based on the calculator on bcae, it looks like the amperage is the voltage that is given divided by the impedance of the speaker . example: 8000 watts into 4 ohms= 44.72 amp (current) 178.89 volts and 178/44=~4 decrease impedance and current goes up, voltage drops. Again, maybe thats not how the volt to amp relationship works, just what i noticed using that calculator. If it does, voltage can be very high or rather low depending on impedance of the sub. and 2nd edit: now im confused, this makes no sense. [/QUOTE]

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