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Does a component set drop ohm load to 2 ohm?
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<blockquote data-quote="helotaxi" data-source="post: 1540411" data-attributes="member: 550915"><p>Around the crossover point, it all depends on the quality of the crossover desing and construction as far as what the impedance will be. The way it is supposed to work is that there is a bit of underlap between the crosover freqs and that both drivers are 3dB down at the crossover point. What the passive filter does is increase its impedance as the frequency moves away from the crossover point. Take the tweeter's high pas filter for example. At the crossover point the tweeter and its filter present twice the nominal impedance of the tweeter alone. As the frequency gets lower, the impedance of the filter gets higher. The midrange works the same way. When you wire the two drivers and their filters in parallel, the rising impedances have little effect on the final impedance "seen" by the amplifier at frequencies outside their passed freq range. Effectively the frequencies are divided between the two drivers and the amp only really "sees" the tweeter at high freqs and the mid at lower freqs.</p></blockquote><p></p>
[QUOTE="helotaxi, post: 1540411, member: 550915"] Around the crossover point, it all depends on the quality of the crossover desing and construction as far as what the impedance will be. The way it is supposed to work is that there is a bit of underlap between the crosover freqs and that both drivers are 3dB down at the crossover point. What the passive filter does is increase its impedance as the frequency moves away from the crossover point. Take the tweeter's high pas filter for example. At the crossover point the tweeter and its filter present twice the nominal impedance of the tweeter alone. As the frequency gets lower, the impedance of the filter gets higher. The midrange works the same way. When you wire the two drivers and their filters in parallel, the rising impedances have little effect on the final impedance "seen" by the amplifier at frequencies outside their passed freq range. Effectively the frequencies are divided between the two drivers and the amp only really "sees" the tweeter at high freqs and the mid at lower freqs. [/QUOTE]
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Does a component set drop ohm load to 2 ohm?
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