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Amplifiers
Damping Factor & impedance
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<blockquote data-quote="thch" data-source="post: 1057551" data-attributes="member: 562032"><p>well, assuming resitive source and load of course!</p><p></p><p>V = Vs Rl / Rl+Rs</p><p></p><p>I = Vs / Rl+Rs</p><p></p><p>P = Vs^2 Rl / (Rl^2 + 2RsRl + Rs^2)</p><p></p><p>ok, to make things easier, Vs can be ignored (Vs is a common term) and we will minimize P^-1 (same as maximizing P)</p><p></p><p>P^-1 ~ Rl + 2Rs + Rs^2 / Rl</p><p></p><p>d(P^-1)/d(Rl) = 0 = 1 + 0 - Rs^2 / Rl^2</p><p></p><p>thus Rs^2 = Rl^2, thus Rs = Rl (for maximum power transfer).</p><p></p><p>of course at AF, you don't really have the same problems with reflections.</p><p></p><p>This wasn't meant to imply tubeamps are better or that a DF of 1 is important. it is the condition required for maximum power transfer, however 1000W at a DF of 100 is typically sufficiently powerful.</p></blockquote><p></p>
[QUOTE="thch, post: 1057551, member: 562032"] well, assuming resitive source and load of course! V = Vs Rl / Rl+Rs I = Vs / Rl+Rs P = Vs^2 Rl / (Rl^2 + 2RsRl + Rs^2) ok, to make things easier, Vs can be ignored (Vs is a common term) and we will minimize P^-1 (same as maximizing P) P^-1 ~ Rl + 2Rs + Rs^2 / Rl d(P^-1)/d(Rl) = 0 = 1 + 0 - Rs^2 / Rl^2 thus Rs^2 = Rl^2, thus Rs = Rl (for maximum power transfer). of course at AF, you don't really have the same problems with reflections. This wasn't meant to imply tubeamps are better or that a DF of 1 is important. it is the condition required for maximum power transfer, however 1000W at a DF of 100 is typically sufficiently powerful. [/QUOTE]
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Damping Factor & impedance
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