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<blockquote data-quote="GreenMachine70" data-source="post: 3985892" data-attributes="member: 558975">Ok guys i&#039;ve been pondering this thought for like two hours now, and i&#039;m quite sure i&#039;ve had a complete and total brain fart. The question is:Q 1. Will the voice coil see less current flow (amps) at the same power level (watts) with i higher impedence (ohm&#039;s)?For referenceV=volts (electromotive force)P=power(watts)R=resistance(ohm&#039;s)I=current(amps)Lets use a dual 2ohm 15&quot; driver for and example and it will be given 3000 watts rms.&nbsp; Thus the amp will see a 1ohm loadI=Sq root (P/R)I=sq root (3000/1)I=54.77ampsnow this is for the driver wired at 1ohm it would theoredicly see 54.77 amps @ 1ohmV=P/IV=3000/54.77V=54.77voltsSo the driver would see 54.77 amps @ 54.77volts wired at 1ohmFor example #2 lets use a 15&quot; dual 1ohm driver at the same power level(3000w rms) This time the amp will see a 2ohm loadsame formulasI=sq root(P/R)I=sq root(3000/2)I=38.72ampsSo @ 2 ohm with the same power level its seeing only 38.72amps. thats 16.05amps less than @ 1ohmV=P/IV=3000/38.72V=77.47voltsSo now with thw increase in resistance we&#039;ve seen a decrease in current and an increase in voltage. With higher voltage level it requires less current to see the same output... theorediclySo in theory I driver wired at a higher ohm load will see less current @ the same power levels. And a decrease in current will cause less of a thermal strain on your coil, making it harder to &quot;smoke&quot; the voice coil? I guess what i&#039;m trying to say is if your sending less curent through your woofer wont it make it less likely to blow? given that everything else is ideal like charging/electrical system, clean non distorted signal etc...Will someone tell me i&#039;m right? i&#039;m sick of thinking<img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite5" alt=":confused:" title="Confused&nbsp; &nbsp; :confused:" loading="lazy" data-shortname=":confused:" />Thanks</blockquote>

[QUOTE="GreenMachine70, post: 3985892, member: 558975"] Ok guys i've been pondering this thought for like two hours now, and i'm quite sure i've had a complete and total brain fart. The question is: Q 1. Will the voice coil see less current flow (amps) at the same power level (watts) with i higher impedence (ohm's)? For reference V=volts (electromotive force) P=power(watts) R=resistance(ohm's) I=current(amps) Lets use a dual 2ohm 15" driver for and example and it will be given 3000 watts rms. Thus the amp will see a 1ohm load I=Sq root (P/R) I=sq root (3000/1) I=54.77amps now this is for the driver wired at 1ohm it would theoredicly see 54.77 amps @ 1ohm V=P/I V=3000/54.77 V=54.77volts So the driver would see 54.77 amps @ 54.77volts wired at 1ohm For example #2 lets use a 15" dual 1ohm driver at the same power level(3000w rms) This time the amp will see a 2ohm load same formulas I=sq root(P/R) I=sq root(3000/2) I=38.72amps So @ 2 ohm with the same power level its seeing only 38.72amps. thats 16.05amps less than @ 1ohm V=P/I V=3000/38.72 V=77.47volts So now with thw increase in resistance we've seen a decrease in current and an increase in voltage. With higher voltage level it requires less current to see the same output... theoredicly So in theory I driver wired at a higher ohm load will see less current @ the same power levels. And a decrease in current will cause less of a thermal strain on your coil, making it harder to "smoke" the voice coil? I guess what i'm trying to say is if your sending less curent through your woofer wont it make it less likely to blow? given that everything else is ideal like charging/electrical system, clean non distorted signal etc... Will someone tell me i'm right? i'm sick of thinking:confused: Thanks [/QUOTE]

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