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choice of amp??
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<blockquote data-quote="mblicker" data-source="post: 75985" data-attributes="member: 545171"><p>well the resistance is determine</p><p></p><p>by two formulae</p><p></p><p>rs= ra +r b</p><p></p><p>if wired in series</p><p></p><p>1/rp= 1/ra + 1/rb if parallel</p><p></p><p>so if you got 4 subs</p><p></p><p>lets say you want 1 ohm.</p><p></p><p>you wire all of them in parallel</p><p></p><p>lets say you want 4 ohms 1)----------2)</p><p></p><p>wire each pair in parallel like so : ----- ----------------</p><p></p><p>3)-----------4)\</p><p></p><p>so that each pair is in parallel but the two pairs are in series at the end</p><p></p><p>so your 1/rp=(1/4+1/4)= 1/2 , therefore rp=2 for each pair</p><p></p><p>and you rs=4 ohms</p></blockquote><p></p>
[QUOTE="mblicker, post: 75985, member: 545171"] well the resistance is determine by two formulae rs= ra +r b if wired in series 1/rp= 1/ra + 1/rb if parallel so if you got 4 subs lets say you want 1 ohm. you wire all of them in parallel lets say you want 4 ohms 1)----------2) wire each pair in parallel like so : ----- ---------------- 3)-----------4)\ so that each pair is in parallel but the two pairs are in series at the end so your 1/rp=(1/4+1/4)= 1/2 , therefore rp=2 for each pair and you rs=4 ohms [/QUOTE]
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