Reply to thread

Message

<blockquote data-quote="helotaxi" data-source="post: 7111326" data-attributes="member: 550915">If you think that being told that you are wrong is &quot;making fun of you&quot; you have some hard lessons to learn in life.&nbsp; Actually this forum is just as full of insecure little know-nothings that have a little fragment of knowledge on a subject and think that makes them right about everything and who then get all butt hurt when the massive gaps in their knowledge or understanding are pointed out.The initial discharge heats the battery slightly and which increases the speed of the chemical reaction giving it a momentary boost that only sometimes is enough to get the car to turn over.&nbsp; But I&#039;m sure you already knew that.&nbsp; What happens if you leave a car sitting for a few weeks or months?&nbsp; Oh that&#039;s right, 99% of the time the battery dies.&nbsp; If the battery was even slightly discharged when the car was parked, it will die much quicker.You&#039;ve created a weak galvanic cell...so what?&nbsp; That is the same principle that a battery works on to begin with.&nbsp; Leave the bulb connected long enough and it will dim and go out.&nbsp; If you then tested the acidity of the vinegar you would find that it had decreased significantly.&nbsp; Letting it sit won&#039;t bring that back either.You are following a logical fallacy here.&nbsp; Voltage and capacity are not the same thing.&nbsp; Just because the voltage might creep back up once the load is removed is not the same thing as energy being &quot;created in the battery.&quot;&nbsp; The battery is still as discharged as it ever was and the only thing that will change that is the application of a voltage at or above the charge voltage of the battery which then forces electrons off the plates and back into the electrolyte.&nbsp; That increases the acidity of the electrolyteI know that.&nbsp; What happens when you apply MORE than 1v?&nbsp; Oh, right, it stores MORE energy.&nbsp; Apply 14v to a 1 Farad cap and it will store 14 Coulombs of energy.&nbsp; It will keep storing that energy until it is discharged by some means involving completing the circuit between the two electrodes.</blockquote>

[QUOTE="helotaxi, post: 7111326, member: 550915"] If you think that being told that you are wrong is "making fun of you" you have some hard lessons to learn in life. Actually this forum is just as full of insecure little know-nothings that have a little fragment of knowledge on a subject and think that makes them right about everything and who then get all butt hurt when the massive gaps in their knowledge or understanding are pointed out. The initial discharge heats the battery slightly and which increases the speed of the chemical reaction giving it a momentary boost that only sometimes is enough to get the car to turn over. But I'm sure you already knew that. What happens if you leave a car sitting for a few weeks or months? Oh that's right, 99% of the time the battery dies. If the battery was even slightly discharged when the car was parked, it will die much quicker. You've created a weak galvanic cell...so what? That is the same principle that a battery works on to begin with. Leave the bulb connected long enough and it will dim and go out. If you then tested the acidity of the vinegar you would find that it had decreased significantly. Letting it sit won't bring that back either. You are following a logical fallacy here. Voltage and capacity are not the same thing. Just because the voltage might creep back up once the load is removed is not the same thing as energy being "created in the battery." The battery is still as discharged as it ever was and the only thing that will change that is the application of a voltage at or above the charge voltage of the battery which then forces electrons off the plates and back into the electrolyte. That increases the acidity of the electrolyte I know that. What happens when you apply MORE than 1v? Oh, right, it stores MORE energy. Apply 14v to a 1 Farad cap and it will store 14 Coulombs of energy. It will keep storing that energy until it is discharged by some means involving completing the circuit between the two electrodes. [/QUOTE]

Verification