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Can someone help me figure out some cubic feet.
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<blockquote data-quote="jdc753" data-source="post: 5305345" data-attributes="member: 572078"><p>For a rectangular cross section you are on the right track. HOWEVER instead of dividing by 12 you want to divide by 1728 (12"x12"x12"=1728in^3) When you multiply your dimensions you get a number and you are also multiplying your units which will need to be taken care of. There is 1728in^3 per ever 1ft^3. For the truck boxes you will have to break the cross section down into a rectangle (top depth x height x width) and then add the area of the triangle front piece ((bottom depth - top depth) x height x width) then add the 2 in^3 numbers you get and divide the sum by 1728in^3 per 1ft^3 to get an over all volume in cubic feet.</p></blockquote><p></p>
[QUOTE="jdc753, post: 5305345, member: 572078"] For a rectangular cross section you are on the right track. HOWEVER instead of dividing by 12 you want to divide by 1728 (12"x12"x12"=1728in^3) When you multiply your dimensions you get a number and you are also multiplying your units which will need to be taken care of. There is 1728in^3 per ever 1ft^3. For the truck boxes you will have to break the cross section down into a rectangle (top depth x height x width) and then add the area of the triangle front piece ((bottom depth - top depth) x height x width) then add the 2 in^3 numbers you get and divide the sum by 1728in^3 per 1ft^3 to get an over all volume in cubic feet. [/QUOTE]
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Can someone help me figure out some cubic feet.
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