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Message: <blockquote data-quote="PSturmer" data-source="post: 3424683" data-attributes="member: 568966">area of a triangle = .5 * (base) * (height)with that right there and the combined knowledge of a standard ported box and the completion of 10th grade geometry its able to be done no problem.since you know width you can just take a cross-sectional view and find the needed area and dimensions of that. and thats all there is to, just summarized a little bit.</blockquote>

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