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Amplifiers
brutus BX1500D
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<blockquote data-quote="spyd3r" data-source="post: 243710" data-attributes="member: 547535"><p>My point exactly.</p><p></p><p>And thats not ohms law my friend. //content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif Its a power law which Ohm did come up with, but that is not the name. Using a simple power equation I=P/V or i^2=P/R does not exactly give you even a rough idea what the amp draws.</p><p></p><p>Im a second year eletrical/computer engineering major, and we have only studied simple amplification theory and manufacturing..and your way isn't even close in giving you the max drawn current.</p><p></p><p>You would have to know the exact parameters of the amp (ie. an interenal resistance seen by a DC power source) to even begin calculating ideal specs.</p><p></p><p>Since its a power amplifier.....you would have some extensive DC, AC, AC node, characteristics to analyze using measured resistance values of resitors...inductor coils...caps. transistor loops...and so on . Then after you calculated all the loop equations you will be able to come up with a peak current draw.</p><p></p><p>And where in the world did you get the 30% efficiency???? What a bogus thing to say...did you design this amplifier that you know how effiecient it is?</p><p></p><p>In the real world the max current draw will be not over 140 amps. No calculations just an educated guess.</p><p></p><p>Best way to determine the max draw is to emailthe tech. (John) at Hifonics and get him to email you a test sheet for that amp.</p><p></p><p>BTW:</p><p></p><p>Not trying to sound negative towards you bassman, but thats a pretty silly thing to say that you came up with the max draw by using a power equation. Just trying to clear up a little eletrical stuff w/o being technical is hard for you to understand the amount of calcualting goes into figurng amps out. //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif</p></blockquote><p></p>
[QUOTE="spyd3r, post: 243710, member: 547535"] My point exactly. And thats not ohms law my friend. [IMG]//content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif[/IMG] Its a power law which Ohm did come up with, but that is not the name. Using a simple power equation I=P/V or i^2=P/R does not exactly give you even a rough idea what the amp draws. Im a second year eletrical/computer engineering major, and we have only studied simple amplification theory and manufacturing..and your way isn't even close in giving you the max drawn current. You would have to know the exact parameters of the amp (ie. an interenal resistance seen by a DC power source) to even begin calculating ideal specs. Since its a power amplifier.....you would have some extensive DC, AC, AC node, characteristics to analyze using measured resistance values of resitors...inductor coils...caps. transistor loops...and so on . Then after you calculated all the loop equations you will be able to come up with a peak current draw. And where in the world did you get the 30% efficiency???? What a bogus thing to say...did you design this amplifier that you know how effiecient it is? In the real world the max current draw will be not over 140 amps. No calculations just an educated guess. Best way to determine the max draw is to emailthe tech. (John) at Hifonics and get him to email you a test sheet for that amp. BTW: Not trying to sound negative towards you bassman, but thats a pretty silly thing to say that you came up with the max draw by using a power equation. Just trying to clear up a little eletrical stuff w/o being technical is hard for you to understand the amount of calcualting goes into figurng amps out. [IMG]//content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif[/IMG] [/QUOTE]
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