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<blockquote data-quote="roarzorz" data-source="post: 6452006" data-attributes="member: 577193"><p>So you purposely do the test wrong to skew the results? Do the test right and you won't have that problem.</p><p></p><p>That entire write up is a joke. Talking about <em>"Quickly disconnect the dummy load of one channel and measure its exact resistance while it is still hot."</em> How silly is that? A totally useless step. Just clamp current output, calculate, and be done.</p><p></p><p>I also don't see where clamping current output on a reactive load was done at all. It only says <em>"The power is the calculated power using the speaker's nominal impedance (4 ohms) and the voltage across the speaker's terminals at the various frequencies. "</em> They're assuming a constant 4ohm impedance which is WRONG. It will not remain constant under a reactive load. You must clamp current output to calculate actual power output.</p><p></p><p>Every idiot online thinks they're a know it all. Have fun with that. :shakes head: :walks out:</p></blockquote><p></p>
[QUOTE="roarzorz, post: 6452006, member: 577193"] So you purposely do the test wrong to skew the results? Do the test right and you won't have that problem. That entire write up is a joke. Talking about [I]"Quickly disconnect the dummy load of one channel and measure its exact resistance while it is still hot."[/I] How silly is that? A totally useless step. Just clamp current output, calculate, and be done. I also don't see where clamping current output on a reactive load was done at all. It only says [I]"The power is the calculated power using the speaker's nominal impedance (4 ohms) and the voltage across the speaker's terminals at the various frequencies. "[/I] They're assuming a constant 4ohm impedance which is WRONG. It will not remain constant under a reactive load. You must clamp current output to calculate actual power output. Every idiot online thinks they're a know it all. Have fun with that. :shakes head: :walks out: [/QUOTE]
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