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Message: <blockquote data-quote="statonburrell" data-source="post: 6512054" data-attributes="member: 610818">i believe the acceleration actually remains constant, so you can use the equations of constant acceleration to solve for your velocity and acceleration.  since you are given your time you should be able to come up with two equations with two unknowns.  solve one of the equations for one unkown then plug that equation into the remaining equation and you should get an answer which will allow you to fully solve your problem.v = vo + atx = xo + vo t + ½ a t^2;      x symbolizes position, x0 is initial which would be zero because it has not taken off yet.x = xo + vo t + ½ (v - vo) t=xo + ½ (v + vo) t= xo + vav tx = xo +½(v + vo) (v- vo)/a2 a (x - xo)= v^2 - vo^2</blockquote>

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